Question

Question 410What is the length of line segment DK to the nearest tenth of an inch?

Answer 1

The Solution:

Given the figure below:

We are required to find the length of DK to the nearest tenth of an inch.

By the Trigonometrical Ratio, we have that:

`\sin 43^o=\frac{\text{opp}}{\text{hyp}}=(16)/(DK)`
`\sin 43^o=(16)/(DK)`

Cross multiplying, we get

`DK\sin 43^o=16`

Dividing both sides by sin43, we get

`DK=(16)/(\sin 43^o)=23.4605\approx23.5^o`

Therefore, the correct answer is 23.5 degrees.