Question

Josiah measured a line to be 18.4 inches long. If the actual length of the line is 19.2

inches, then what was the percent error of the measurement, to the nearest tenth of a
percent?

Answer 1

Given:

The actual measurement is 19.2 inches.

The new measurement is 18.4 inches.

To find the percent error:

So, the formula is,

`\begin{gathered} \frac{Actual-New}{\text{Actual}}*100=(19.2-18.4)/(19.2)*100 \\ =(0.8)/(19.2)*100 \\ =(80)/(19.2) \\ =4.166667 \\ \approx4.2 \end{gathered}`

Hence, the percent error is 4.2%.