How many moles of iron(lll) hydroxide contain 9.45 x10^25 atoms? Include units and name of atoms/molecule.

Question

asked Sep 12, 2023 166k views

1 Answer

Rcapote · Answer 1 · 2023-09-19T06:36:06+0000

We are required to calculate the number of moles of iron (III) hydroxide.

We are given the number of atoms = 9.45x10^25.

We also know that 1 mol = 6.022x10^23 atoms

Iron(III) hydroxide moles = 9.45x10^25/6.022x10^23

= 156.925 mol of Iron (III) hydroxide