Question

In circle C, BC = 6 and angle ACB = 120 degrees. what is the area of the shaded sector?

Answer 1

`\text{Area of sector = 12}\pi\text{ (option C)}`Step-by-step explanation:

Area of sector = θ/360 × πr²

θ = m∠ACB = 120°

radius = r = 6

`\text{Area of sector = }(120)/(360)*\pi*6^2`
`\begin{gathered} \text{Area = }(1)/(3)*\pi*36 \\ Area\text{ = }\pi*(36)/(3)\text{ } \end{gathered}`
`\begin{gathered} Area\text{= }\pi*12 \\ \text{Area of sector = 12}\pi\text{ (option C)} \end{gathered}`