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Select the correct answer from each drop-down menu.In the first box it’s either (equal to) or (not equal to)In the Second box it’s either (are) or (are not)

Select the correct answer from each drop-down menu.In the first box it’s either (equal-example-1
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User Elkvis
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1 Answer

5 votes

To find h(k(x)), we have to replace the x-variable of h(x) with the function k(x).


\begin{gathered} h(k(x))=5(\sqrt[]{5x+1})^2-1=5(5x+1)-1=25x+5-1 \\ h(k(x))=25x+4 \end{gathered}

Then, find k(h(x)) using the same process.


\begin{gathered} k(h(x))=\sqrt[]{5(5x^2-1)+1}=\sqrt[]{25x^2-5+1} \\ k(h(x))=\sqrt[]{25x^2-4} \end{gathered}

As you can observe, the functions obtained are not equal.

Therefore, h(k(x)) is not equal to k(h(x)).

Also, the functions h and k are not inverse functions because the coefficient 5 would be as a denominator.

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User Genericrich
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