Question

Given parallelogram ABCD; ED=7x and BD=16x-38. Find BD. * B C E А D

Answer 1

`\begin{gathered} \text{Note since it's a paragellogram then we have.} \\ ED\text{ = }(1)/(2)* BD \\ 7x\text{ = }(1)/(2)*(16x-38) \\ 7x\text{ =}((16x-38))/(2) \\ By\text{ cross multiplying we have.} \\ 7x\text{ }*\text{ 2 = 16}x\text{ -38} \\ 14x\text{ = 16}x\text{ - 38} \\ By\text{ collecting like term we have.} \\ 14x-\text{ 16}x\text{ = -38} \\ -2x\text{ = -38} \\ x\text{ = }(-38)/(-2)\text{ = 19} \\ x\text{ = 19} \\ \text{Therefore, BD = 16}x\text{ - 38} \\ \text{ BD = 16}*19\text{ - 38} \\ \text{ BD = 304 - 38} \\ \text{ BD =}266 \end{gathered}`