Question

Please find amplitude period and phase shifty=sin(2x-pi/2)

Answer 1

For the sinusoidal function:

`y=A\sin (Bx+C)+D`

we have that:

A represents the amplitude

2pi/B represents the Period

C is the phase shift

D is the vertical shift.

In this case, we have the following equation:

`y=\sin (2x-(\pi)/(2))`

then, the amplitude is A = 1.

For the period, we have the following:

`\begin{gathered} B=2 \\ \Rightarrow(2\pi)/(B)=(2\pi)/(2)=\pi=\text{Period} \\ \end{gathered}`

thus, the period is pi.

Finally, notice that C = -pi/2, thus, the phase shift is -pi/2