Question

Find the equation of a line that contains the points (-2, 2) and (-6,-5). Write the equation in slope-intercept form, usingfractions when required

Answer 1

Step-by-step explanation

Lets first find the slope:

`m=(2-(-5))/(-2-(-6))=(2+5)/(-2+6)=(7)/(4)`

Now let's use the point-slope formula:

`\begin{gathered} y-2=(7)/(4)(x-(-2)) \\ y-2=(7)/(4)(x+2) \\ y-2=(7)/(4)x+(7)/(2) \\ y=(7)/(4)x+(7)/(2)+2 \\ y=(7)/(4)x+(7)/(2)+(4)/(2) \\ y=(7)/(4)x+(11)/(2) \end{gathered}`

Answer

`y=(7)/(4)x+(11)/(2)`