Question

-TB +6r) = 14-1 .1+(3), GREMOR -R=17 3-18R=14.R 190 3-18 R&R=14-RAR Ral -3-172314 -3-178+3=1443 -4k + 2(5k - 6) = -3k - 39 n 1=-212

Answer 1

We need to find k, so we have that

`\begin{gathered} -4k+2(k-6)=-3k-39_{} \\ -4k+2k-12=-3k-39_{} \\ -4k+2k+3k=-39+12_{} \\ k=-27_{} \end{gathered}`

So the answer is k=-27.