Question

Use point-slope form to write the equation of a line that passes through the point (−20,−4) with slope -4/3

Answer 1

→Given slope, m = -4/3

and (x;y) intercepts = (-20,-4)

we will use the following formula.

Y = mx +c

y = -4/3x +c

→We need to find the y intercep (c) , by plugging in the (x;y) = (-20;-4)

-4 = -4/3(-20) +c

-4 = (80/3) +c

-4 -(80/3) = c

therefore c = -92/3

→Finally, our equation will be :

y = -4/3x -92/3