Question

While doing more research on airline tickets, Luis found another airline that had a special. If the family purchased the tickets within the next 48 hours, the price of the tickets would be reduced by 15%. This airline charges $50 round- trip for each bag that is checked, so he wrote the equation 4(t + 25) = 4(t + 50) – 4(0.15t) to determine the price per ticket for which the two airlines have the same total cost. What ticket price will have the same total cost (including checked bags) for both airlines? $500.00 $333.33 $83.67 O $60.00 $41.67 $166.67 E

Answer 1

$166.67

Step-by-step explanation

We have that the equation that Luis has used to represent the given situation is:

4(t + 25) = 4(t + 50) - 4(0.15t)

where t = price per ticket for which the two airlines have the same total cost

From the question, we have to find the ticket price, t.

We do that by simplifying the equation given.

That is:

4(t + 25) = 4(t + 50) - 4(0.15t)

Expand the bracket:

4t + 100 = 4t + 200 - 0.6t

Collect like terms:

4t - 4t + 0.6t = 200 - 100

0.6t = 100

t = 100 / 0.6

t = $166.67

That is the ticket price that satisfies the situation.