Question

Need to learn how to solve these mixed fractions at least 1 subtraction, 1 multiplication and addition Please so I can do the restThanks

Answer 1

`\begin{gathered} 3(1)/(2)+4=7(1)/(2) \\ (3)/(8)+(1)/(4)=(5)/(8) \\ 9(1)/(4)-5(1)/(2)=3(3)/(4) \\ 3(3)/(5)-(4)/(5)=2(4)/(5) \\ 6*4(1)/(2)=27 \\ 7*2(1)/(8)=14(7)/(8) \end{gathered}`

Explanation:

In the case of the sum for mixed numbers, both the integer part and the fractional part must be added when adding the fractions we must cross multiply and add in the numerator and the denominator is the product of the denominators, just like this:

`\begin{gathered} 3(1)/(2)+4=\mleft(3+4\mright)\mleft((1)/(2)+0\mright)=7(1)/(2) \\ (3)/(8)+(1)/(4)=(3\cdot4+1\cdot8)/(32)=(12+8)/(32)=(20)/(32)=(5\cdot4)/(8\cdot4)=(5)/(8) \end{gathered}`

In the case of subtraction for mixed numbers, both the integer part and the fractional part must be subtracted. When subtracting fractions, we must cross multiply and subtract in the numerator and the denominator is the product of the denominators, just like this:

`\begin{gathered} 9(1)/(4)-5(1)/(2)=\mleft(9-5\mright)\mleft((1)/(4)-(1)/(2)\mright)=4\mleft((1\cdot2-1\cdot4)/(8)\mright)=4\mleft((-2)/(8)\mright)=4-(1)/(4)=3\mleft(1-(1)/(4)\mright)=3\mleft((4)/(4)-(1)/(4)\mright)=3(3)/(4) \\ 3(3)/(5)-(4)/(5)=(3-1)\mleft((3)/(5)+1-(4)/(5)\mright)=2\mleft((3)/(5)+(5)/(5)-(4)/(5)\mright)=2(4)/(5) \end{gathered}`

In the case of multiplication, both the whole part and the fractional part are multiplied and then added.

`\begin{gathered} 6*4(1)/(2)=\mleft(6\cdot4\mright)+\mleft(6\cdot(1)/(2)\mright)=24+3=27 \\ 7*2(1)/(8)=\mleft(7\cdot2\mright)+\mleft(7\cdot(1)/(8)\mright)=14+(7)/(8)=14(7)/(8) \end{gathered}`