Question

Hi there, I am lost here and need some help

Answer 1

The area of triangle ABC in terms of a and b is:

`A=(1)/(2)ab`

The area of triangle ABC in terms of c and h is:

`A=(1)/(2)ch`

Equating the areas gives:

`(1)/(2)ab=(1)/(2)ch`

Isolating h gives:

`\begin{gathered} ab=ch \\ h=(ab)/(c) \end{gathered}`

Hence the prove.