Question

Given the following formula, solve for v.s = 1/2a2v + cs + cA. v = -------2a22(s - c)B. v = --------a2s -- cC. v = --------2a22( s + c)D. v = ----------a2

Answer 1

Given data:

The given expression is s=1/2 a^(2)v +c.

The given expression can be written as,

`\begin{gathered} s=(1)/(2)a^2v+c \\ (1)/(2)a^2v=s-c \\ v=(2(s-c))/(a^2) \end{gathered}`

Thus, the option (A) is correct.