Question

The population mean annual salary for a environmental compliance specialist is about 60,500A random sample of 43 specialist is drawn from the population. What is the probability that the sample mean is less than 58,000

Answer 1

To answer this question, we first have to find the sample z score, and the formula is:

`z=\frac{((x-\mu)/(\sigma))}{\sqrt[]{n}}`

Substituting the given values into the formula above:

`\begin{gathered} z=\frac{(58,000-60,500)/(5800)}{\sqrt[]{43}} \\ z=-0.0657 \end{gathered}`

So by using the z-score calculator, the probability at a z-score less than -0.0657 is

`0.4738`