Question

Please help meif you can't read it it says -138=-6(6b-7)

Answer 1

We have the following:

`\begin{gathered} -138\ge-6\cdot(6b-7) \\ \end{gathered}`

solving for b:

`\begin{gathered} -6\cdot(6b-7)\le-138 \\ -(6)/(6)\cdot(6b-7)\le-(138)/(6) \\ -(6b-7)\le-23 \\ (6b-7)\ge23 \\ 6b-7+7\ge23+7 \\ 6b\ge30 \\ b\ge(30)/(6) \\ b\ge5 \end{gathered}`

Therefore, the interval is:

`\lbrack5,\infty)`