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Find the area of the figure given to the right. The hexagon is regular. Round to the nearest whole number.

Find the area of the figure given to the right. The hexagon is regular. Round to the-example-1

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We can divide the hexagon into 6 equilateral triangles, and call the side 'x'. I will draw the situation:

Every line is x because the hexagon is regular (all sides have the same length). Therefore we can find x, because two times x is 18'':


2x\text{ = 18}
x\text{ = 9 inches}

The hexagon has the same area of 6 equilateral triangles with the side equal to x. The formula of the area of an equilateral triangle is:


Area\text{ = }\frac{x^2\sqrt[]{3}}{4}

Therefore the area of the hexagon will be:


\text{AreaHexagon = 6}*\frac{x^2\sqrt[]{3}}{4}^{}
\text{AreaHexagon = 6}*\frac{9^2\sqrt[]{3}}{4}^{}
\text{AreaHexagon }\cong210.44\text{ square inches}

Rounding it will be 210 square inches.

Find the area of the figure given to the right. The hexagon is regular. Round to the-example-1
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User Taiesha
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