Question

Let O be an angle in quadrant II such that csc =4"Find the exact values of tan 0 and cos 0.

Answer 1

`\begin{gathered} \csc (\theta)=(hypotenuse)/(opposite)=(9)/(4) \\ \end{gathered}`

The tangent function is given by:

`\tan (\theta)=(opposite)/(adjacent)=-\frac{4}{\sqrt[]{65}}`

And the cosine function is:

`\cos (\theta)=(adjacent)/(hypotenuse)=-\frac{\sqrt[]{65}}{9}`