Question

The motion in one dimension of a vehicle is recorded on a horizontal axis Ox . It starts from rest at x = -20 m and moves in the positive direction with an acceleration a = 5 m / s² to a final position x , during a time interval t = 10s . What is its final position ( x , = ? ) ?

Answer 1

Given:

The initial distance is

`x_0=-20\text{ m}`

The initial velocity is

`v_0=\text{ 0m /s}`

The acceleration is a = 5 m/s^2.

The time interval is t = 10 s.

To find the final position, x.

Step-by-step explanation:

The final position can be calculated as

`\begin{gathered} x=x_0+v_0t+(1)/(2)at^2 \\ =-20+0*10+(1)/(2)*5*(10^)^2 \\ =230\text{ m} \end{gathered}`

Thus, the final position is 230 m