Question

15. Gabriel has these cans of soup in his kitchen cabinet.2 cans of tomato soup3 cans of chicken soup2 cans of cheese soup2 cans of potato soup1 can of beef soupGabriel will randomly choose one can of soup. Then he will putit back and randomly choose another can of soup. What is theprobability that he will choose a can of tomato soup and then acan of cheese soup?P (tomato soup and cheese soup) P =P(potato soup and beef or chicken soup) P =

Answer 1

The probability formula is given by:

`\text{ P(E) = }\frac{\text{ N(Required outcome)}}{\text{ N(Total outcome)}}`

Total number of cans of soup = 2 + 3 + 2 + 2 + 1 = 10

`\begin{gathered} \text{ P(tomato soup and ch}eese\text{ soup) =}(2)/(10)*(2)/(10)=(4)/(100)=(1)/(25) \\ \text{ P(potato soup and beef or chicken soup) = }(2)/(10)*(1)/(10)+(3)/(10) \end{gathered}`
`\begin{gathered} =\text{ }(2)/(100)+(3)/(10)=(32)/(100) \\ =(8)/(25) \end{gathered}`

Therefore,

P(tomato soup and cheese soup) = 1/25

P(potato soup and beef or chicken soup) =8/25