Question

1. If a colorblind female (XcXc) marries a normal male (XY), what are the chances of normal children? Colorblind children? Do a Punnet square to find the answer.

Answer 1

Female genotype- XcXc (colorblind)

Male genotype- XY (normal)

If we cross multiply these genotypes, the resulting offsprings would be:

XcX, XcX, XcY, XcY

The chances of having colorblind children are: 50%

XcY, XcY- all male

Normal children: 50%

XcX, XcX- all female (Carrier)