asked 53.9k views
3 votes
Which equation has no real solutions?(А)2x2+2x+15= 02x2 + 5x - 3=0© x2 + 7x+2=0x2 - 4x + 2 = 0

Which equation has no real solutions?(А)2x2+2x+15= 02x2 + 5x - 3=0© x2 + 7x+2=0x2 - 4x-example-1
asked
User Ulrichb
by
8.5k points

1 Answer

1 vote

We are asked to find out which of the given quadratic equation has no real solutions.

Recall that a quadratic equation has no real solutions if the discriminant is less than 0.

The discriminant is given by


d=b^2-4ac

Where a, b, and c are the coefficients of the quadratic equation.

Let us analyze each of the given quadratic equations.

Option A:


2x^2+2x+15=0

The coefficients are

a = 2

b = 2

c = 15

The discriminant is


\begin{gathered} d=b^2-4ac \\ d=2^2-4(2)(15) \\ d=4-120 \\ d=-116 \end{gathered}

As you can see, the discriminant is less than 0, therefore, this quadratic equation has no real solutions.

Therefore, the correct answer is option A.

answered
User Mo Kargas
by
8.2k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.