Question

Can you please send me the

Answer 1

we have the expression

`(106+15i)/(-8+3i)`

step 1

Multiplicate numerator and denominator by the conjugate of denominator

so

`(106+15i)/(-8+3i)\cdot(-8-3i)/(-8-31)`

Remember that

i^2=-1

so

`(106+15i)/(-8+3i)\cdot(-8-3i)/(-8-31)=(-848-318i-120i-45i^2)/(64-9i^2)`
`\begin{gathered} (-848-318i-120i-45i^2)/(64-9i^2)=(-848-438i+45)/(64+9) \\ \\ =(-438i-803)/(73) \end{gathered}`

Simplify

`(-438i-803)/(73)=(-438i)/(73)-(803)/(73)=-6i-11`

the answer is

-6i-11