Question

How to solve 5x^2-45=0

Answer 1

`\begin{gathered} 5x^2-45=0 \\ a=5 \\ b=0 \\ c=-45 \\ \\ x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ x=\frac{-0\pm\sqrt[]{0^2-4(5)(-45)}}{2(5)} \\ x=\frac{\pm\sqrt[]{900}}{10} \\ x=(\pm30)/(10) \\ x=\pm3 \end{gathered}`