Question

How do I do the synthetic division for this equation with a missing power

Answer 1

`(k^3-17k+32)/(k+5)`

Using synthetic division:

`\begin{gathered} k+5=0 \\ k=-5 \end{gathered}`

Therefore:

`(k^3-17k+32)/(k+5)=k^2-5k+8-(8)/(k+5)`