Question

Special right triangles Find the missing side lengths. Leave your answers as radicals in simplest form? The image is down below.

Answer 1

Given:

To Find:

Missing side lengths

Step-by-step explanation:

`\begin{gathered} \cos \theta=\frac{Opposite\text{ side}}{\text{hypotenuse side}} \\ \cos 30\degree=(AB)/(BC) \\ \frac{\sqrt[]{3}}{2}=\frac{2\sqrt[]{3}}{BC} \\ BC=2\sqrt[]{3}*\frac{2}{\sqrt[]{3}} \\ x=4 \end{gathered}`
`\begin{gathered} \sin \theta=\frac{Opposite\text{ side}}{\text{hypotenuse side}} \\ \sin 30\degree=(AC)/(BC) \\ (1)/(2)=(AC)/(4) \\ AC=(4)/(2) \\ y=2 \end{gathered}`

Final Answer:

`\begin{gathered} x=4 \\ y=2 \end{gathered}`