asked 116k views
4 votes
The average number of miles flown by a Boeing 777 which is operated by a commercial airline over its lifetime is 52,500,000 miles. Assume these mileage amounts have a normal probability distribution with a standard deviation of 2,975,000 miles, and find the mileage that eighty percent of the 777 fleet exceeds over the course of its lifetime in commercial aviation.

asked
User Nahidf
by
8.1k points

1 Answer

2 votes

Solution:

Given:


\begin{gathered} \mu=52,500,000 \\ \sigma=2,975,000 \end{gathered}

From Z-score table, the Z-score of 80% is 0.842

Hence, using the Z-score formula,


\begin{gathered} Z=(x-\mu)/(\sigma) \\ 0.842=(x-52,500,000)/(2,975,000) \\ Cross\text{ multiplying;} \\ x-52,500,000=0.842*2,975,000 \\ x-52,500,000=2,504,950 \\ x=2,504,950+52,500,000 \\ x=55,004,950miles \end{gathered}

Therefore, the mileage that eighty percent of the 777 fleet exceeds over the course of its lifetime in commercial aviation is 55,004,950 miles

answered
User Ketema
by
7.7k points
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