Question

What is sin θ if cos θ= √2/2 And θ is in 0< θ< π /2?

Answer 1

`\begin{gathered} 2^2=(\sqrt[]{2})^2+opposite^2 \\ 4=2+O^2 \\ 4-2=O^2 \\ O^2=2 \\ O=\sqrt[]{2} \end{gathered}`
`\begin{gathered} \text{Sine }\theta=\frac{opposite}{\text{hypotenuse}} \\ \text{Sine }\theta=\frac{\sqrt[]{2}}{2} \end{gathered}`