Question

i have a triangle whose is 19.9 and a height of 19. what is the the mease of the diagonal to nearest 10th of an inch?

Answer 1

We will find it as follows:

`d^2=19.9^2+19^2\Rightarrow d=\sqrt[]{19.9^2+19^2}\Rightarrow d\approx27.5`

So, the diagonal will be approximately 27.5 inches.