Question

The value of y is inversely proportional to the value of x. When y = 42, x = 6. What is the value of y when x = 9? 45, 28, 63, 252

Answer 1

`y=28`

1) We know that an inversely proportional variation can be written as:

`y=k((1)/(x))`

2) Note that we were also told that when y= 42, x=6 so let's find the quantity of k:

`\begin{gathered} y=k((1)/(x)) \\ 42=k((1)/(6)) \\ 42=(k)/(6) \\ k=252 \end{gathered}`

2.2) Now, let's find the quantity of y when x=9:

`\begin{gathered} y=k((1)/(x)) \\ y=252\cdot((1)/(9)) \\ y=28 \end{gathered}`

Thus, the answer is y=28