Question

If g(n) varies inversely with n and g(n)- 12 when n-3 then find the value of n wheng(n)= 6Round final answer to the tenths place. If answer is a whole number then put a zeroin the tenths place

Answer 1

`\begin{gathered} g(n)\propto(1)/(n) \\ g(n)=(k)/(n),(\text{where k = constant) } \end{gathered}`
`\begin{gathered} \text{when} \\ g(n)=12 \\ n=3 \\ g(n)=(k)/(n) \\ 12=(k)/(3) \\ k=12(3) \\ k=36 \end{gathered}`
`\begin{gathered} g(n)=(36)/(n) \\ \text{constant of proportionality} \end{gathered}`

find the value of n when g(n) = 6

`\begin{gathered} g(n)=6 \\ g(n)=(36)/(n) \\ n=(36)/(g(n)) \\ n=(36)/(6) \\ n=6.0 \end{gathered}`

Therefore the value of n = 6.0 (tenth