Question

Calculate the maximum mass of ammonium sulphate that can be produced by the reaction

Answer 1

2694.56grams.

Explanations

Given the balanced chemical reaction between sulphuric acid and ammonia expressed as:

`H_2SO_4+2NH_3\rightarrow(NH_4)_2SO_4`

Given the following parameter

moles of ammonia = 58.82 moles

Mass of sulphuric acid = 2kg = 2000grams

Determine the moles of H2SO4

`\begin{gathered} moles\text{ of H}_2SO_4=\frac{mass}{molar\text{ mass}} \\ moles\text{ of H}_2SO_4=\frac{2000g}{98.079g\text{/}mol} \\ moles\text{ of }H_2SO_4=20.392moles \end{gathered}`

Since the moles of sulphuric acid is less than the moles of one atom of ammonia, hence sulphuric acid will be the limiting reactant.

Determine the maximum mass of ammonium sulphate

`\begin{gathered} Mass=mole* molar\text{ mass} \\ Mass\text{ of ammonium sulphate}=20.932moles*(132.14g)/(mol) \\ Mass\text{ of ammonium sulphate}=2694.56grams \end{gathered}`

Hence the mass of ammonium sulphate produced is approximately 2694.56grams