Question

Solve by substitution x+3y=-1y=-1/3x-1/3

Answer 1

Given the system of equations:

`\begin{cases}x+3y=-1\ldots(1) \\ y=-(1)/(3)x-(1)/(3)\ldots(2)\end{cases}`

Using (2) in (1):

`\begin{gathered} x+3(-(1)/(3)x-(1)/(3))=-1 \\ x-x-1=-1 \\ -1=-1 \end{gathered}`

There are infinite solutions.