Question

The football teams consists of 15 seniors and 7juniors. The coach has decided to randomly choose 4players to represent the team at this year's pep rally.What is the probability that one senior and 3 juniorswill be chosen?

Answer 1

The team consists of 15 seniors. Probability of choosing 1 senior becomes

`\begin{gathered} \text{Probability = }\frac{\exp ected\text{ outcome}}{\text{total outcomeP}} \\ P(S)=(1)/(15) \end{gathered}`

The team also consists of 7 juniors. Probability of choosing 3 juniors

`P(J)=(3)/(7)`

And the probability that one senior and 3 juniors will be chosen becomes

`\begin{gathered} P(S\text{ and J) = P(S) }* P(J) \\ =(1)/(15)*(3)/(7) \\ =(1)/(5)*(1)/(7) \\ =(1)/(35) \end{gathered}`

Hence the answer is

`(1)/(35)`