Question

In APQR, the measure of ZR=90°, RQ = 55, PR = 48, and QP = 73. What ratio represents the sine of ZQ?

Answer 1

To find the angle Q we can us the sin law so:

`(\sin (Q))/(48)=(\sin (90))/(73)`

So we can solve for Q so:

`\begin{gathered} \sin (Q)=(48)/(73) \\ \measuredangle Q=\sin ^(-1)(0.6) \\ \measuredangle Q=36.87 \end{gathered}`