Write the equation of the line passing through point (-6,0) and perpendicular to y= 3/2x

Question

asked Jan 24, 2023 37.0k views

1 Answer

Jason Van Der Zeeuw · Answer 1 · 2023-01-28T02:30:46+0000

First, let's find the slope of our line.

Remember that the product between lines that are perpendicular is -1.

This way,

$(3)/(2)\cdot m=-1\rightarrow3m=-2\rightarrow m=-(2)/(3)$

Using the slope-point form,

$y-0=-(2)/(3)(x+6)\rightarrow y=-(2)/(3)x-4$

Therefore, the line that passes through (-6,0) and that is perpendicular to y=(3/2)x is:

Answer: Option B