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What is the Vertex of the given Quadratic Function?Function = - (x+3)^2 + 2 (-3,2)(-2,3)(2-3)(3,2)

What is the Vertex of the given Quadratic Function?Function = - (x+3)^2 + 2 (-3,2)(-2,3)(2-3)(3,2)
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What is the Vertex of the given Quadratic Function?Function = - (x+3)^2 + 2 (-3,2)(-2,3)(2-3)(3,2)

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User Linkmichiel
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the vertex is (-3,2) because x+3=0 implies x=-3 and y-2=0 implies y=2

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User Xiaoming
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