Question

Find the focus of the parabola: f(x) = 14(x – 3)2 + 1

Answer 1

f(x) = 14(x-3)^2 + 1

For any parabola expressed in the form y = a(x-b)^2+c, the focus coordinates are given by: (b,c+1/4a)

Therefore, the focus is: (3,1+1/4*14) = (3,57/56)