Question

The diagram of an isosceles trapezoid is labeled below. If the area of the trapezoid is 168 square units, the what is the height, h, out of the trapezoid?

Answer 1

`\begin{gathered} \text{Area =}((B+b)\cdot h)/(2) \\ 2\cdot\text{Area}=(B+b)\cdot h \\ h=(2\cdot Area)/(B+b) \\ h=(2\cdot168)/(19+9) \\ h=(336)/(28) \\ h=12 \\ \end{gathered}`