Question

Iliana multiplied 3p – 7 and 2p^2 – 3p – 4. Her work is shown in the table.Which is the product?6p^3 + 23p^2 + 9p + 286p^3 – 23p^2 – 9p + 286p^3 – 23p^2 + 9p + 286p^3 + 23p^2 – 9p + 28

Answer 1

The given multiplication can be expressed as,

`(3p-7)(2p^2-3p-4)`

On multiplying, we get,

`\begin{gathered} (3p-7)(2p^2-3p-4)=(3p*2p^2)-(3p*3p)-(4*3p)-(7*2p^2)+(7*3p)+(7*4) \\ =6p^3-9p^2-12p-14p^2+21p+28 \\ =6p^3-23p^2+9p+28 \end{gathered}`

Thus, the third option is correct.