Question

7) What is the equation of a circle centered(4,-3) with a radius of 4?

Answer 1

To determine the equation of a circle

`(x-a)^2+(y-b)^2=r^2`
`\text{centre (a , b) = (4 , -3) and radius r = 4}`
`\begin{gathered} (x-a)^2+(y-b)^2=r^2 \\ (x-4)^2+(y-(-3))^2=4^2 \\ (x-4)^2+(y+3)^2=16 \\ (x-4)(x-4)+(y+3)(y+3)=16_{} \end{gathered}`