Question

Given the two points: (0,6) and (6, 18), write the equation of the line.y = 2x + 6y = 1/2 x + 6y = 1/3 x + 6y = 3x + 6

Answer 1

Given that to find the equation of the line that passes through the two points.

`\left(0,6\right),\left(6,18\right)`

we know that,

Equation of the line that passes through the two points (x1,y1) and (x2,y2) is

`(y-y1)/(y2-y1)=(x-x1)/(x2-x1)`

Substitute the values, x1=0, y1=6, x2=6, y2=18

we get,

`(y-6)/(18-6)=(x-0)/(6-0)`
`(y-6)/(12)=(x)/(6)`
`y-6=(12x)/(6)`
`y-6=2x`
`y=2x+6`

Answer is: The required equation of a line is y = 2x + 6.