Question

What is the energy of a photon (J) that has a frequency of 4.39 × 10^19 Hz?A) 2.91 × 10-14B) 2.91 × 1020C) 6.83 × 10-12 D) 2.91 × 10-52E) 2.91 × 1054

Answer 1

2.91 × 10⁻¹⁴ J

Procedure

The energy of a photon can be calculated using the following equation:

`E=hf`

Where:

E is energy (J)

h is Planck's constant: 6.62607015 × 10⁻³⁴ (m²kgs⁻¹)

f is the frequency (Hz)

Given our data, the equation will be

`E=6.62607015*10^(-34)(m^2kg)/(s)*(4.39*10^(19)Hz)=2.91*10^(-14)J`