Question

Which of the following is the solution to |x+11|<17 ?

Answer 1

Given:

The inequality is,

`\lvert x+11\rvert<17`

Solve the inequality,

`\begin{gathered} \lvert x+11\rvert<17 \\ Apply\text{ absolute rule, }\mathrm{If}\: |x|\: <\: a,for\: a>0\: \mathrm{then}\: -a\: <\: x\: <\: a \\ -17-17\text{ and x+11<17} \\ x>-17-11\text{ and x<17-11} \\ x>-28\text{ and x< }6 \end{gathered}`

The solution of given inequality is,

`x<6,x>-28`

Answer: Option D.