asked 8.9k views
1 vote
Using l'hopital rulelim x->0 (xe^x)/x^2

asked
User Dudi
by
8.2k points

1 Answer

5 votes

hello


\lim _(x-0)=(xe^x)/(x^2)=((dx)/(dx)\cdot e^x)/(2x)=(1\cdot e^x)/(2x)=(e^x)/(2x)

answered
User Nathan Gaskin
by
9.0k points
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.