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The perimeter of a rectangular painting is 302 centimeters. If the width of the painting is 68 centimeters, what is it’s length?

asked
User Jacka
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8.5k points

1 Answer

7 votes

SOLUTION

The perimeter of the rectangle is given as 302.

It is given that the width is 68.

Recal the formula for perimeter of a rectagle:


P=2(l+w)

Substituting values gives:


302=2(l+68)

Solve the equation for l.


\begin{gathered} (302)/(2)=l+68 \\ 151=l+68 \\ l=151-68 \\ l=83 \end{gathered}

Therefore the length of the rectangle is 83

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