Question

A small homemade electromagnet has a lifting force of 3.6 N. If the current through the coil is doubled and the number of loops is tripled, what will the lifting force become?

Answer 1

We will determmine the lifting force as follows:

`F=(NI\mu)/(L)`

Now, using tthe equation for the magnetic force we will have the following scenario:

`F=(3N\cdot2I\mu)/(L)\Rightarrow F=6\cdot(NI\mu)/(L)`
`\Rightarrow F=3.6\cdot6\Rightarrow F=21.6`

Thus:

`F\approx22`

So, the lifting force will be exactñy 21.6N, that is approximately 22N.