Find 2 integers between which each radical belongs √(91)

Question

Find 2 integers between which each radical belongs
`√(91)`

Answer 1

9 and 10

Step-by-step explanation:

First, determine two perfect squares: One less than and one greater than 91.

`81<91<100`

Take the square roots:

`\begin{gathered} \sqrt[]{81}<\sqrt[]{91}<\sqrt[]{100} \\ =9<\sqrt[]{91}<10 \end{gathered}`

Thus, radical √91 is between integers 9 and 10.