Question

Solve the triangle whit the given parts g = 6.9, h = 13.9, | = 16.0G Round to 2 delcmal places.

Answer 1

We want to solve the given triangle;

`\begin{gathered} cos\angle G=(h^2+i^2-g^2)/(2ih) \\ =0.9029 \\ \angle G=cos^(-1)0.9029=25.46^o \end{gathered}`
`\begin{gathered} cos\angle H=(g^2+i^2-h^2)/(2gi) \\ =0.5 \\ H=cos^(-1)0.5=60^o \end{gathered}`

Thus;

`\angle I=180-60-25.46=94.54^o`

Thus the full measures of the triangle are;

`\begin{gathered} g=6.9,h=13.9,i=16.0 \\ \angle G=25.46^o,\angle H=60^o,\angle I=94.54^o \end{gathered}`