asked 162k views
3 votes
What is the freezing point of a 0.800m aqueous solution of glucose, given that Kf for water is 1.86°C/m? Show your work.

asked
User Shevi
by
8.4k points

1 Answer

4 votes

To determine the freezing point we can apply the following formula that relates the molality to the freezing point of water:


\Delta T_f=K_f* m

Where,

m is the molality

Kf is the freezing point of water

DeltaTf= Freezing point

We replace the known data:


\Delta T_f=1.86(\degree C)/(m)*0.800m=1.49\degree C

So, the freezing point of the solution will be 1.49°C

answered
User Anuj Khandelwal
by
8.6k points
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